Write a program that takes nouns and forms their plurals on the basis of these rules:
a. if noun ends in "y", remove the "y" and add "ies".
b. if noun ends in "s", "ch", or "sh", add "es".
c. in all other cases, just add "s".
print each noun and its plural. try the following data:
chair dairy boss circuis fly dog church clue dish

def nounToplural(tex):

   import re

   

   text = tex.split()

   new = []

   for word in text:

       if re.findall(r"y\b", word):

           word = re.sub(r"y\b", 'ies' ,word)

           new.append(word)

       

       elif re.findall(r"ch\b", word):

           word = re.sub(r"ch\b", 'ches' ,word)

           new.append(word)

       elif re.findall(r"sh\b", word):

           word = re.sub(r"sh\b", 'shes' ,word)

           new.append(word)

       elif re.findall(r"s\b", word):

           word = re.sub(r"s\b", 'ses' ,word)

           new.append(word)

       else:

           word = word + 's'

           new.append(word)

   result = []

   for i in text:

       for j in new:

           if new.index(j) == text.index(i):

               result.append( (i,j) )

           

           

   print(result)

str = "chair dairy boss circuis fly dog church clue dish"

nounToplural(str)

Explanation:

We made use or Regular Expressions which is simply a special sequence of characters that helps you match or find other strings or sets of strings, by using a specialized syntax held in a pattern.

Firstly, define the function and import the regular expression module, split the text into a list and create an empty list to hold the plural list.

For every word in the list  we check with IF statements and regular expressions to find out what they end with.

 if re.findall(r"y\b", word):

           word = re.sub(r"y\b", 'ies' ,word)

           new.append(word)

The above IF block checks if a noun ends with 'y', if it does it replaces the 'y' with 'ies' and ads it to the new list.

If it does not, ot moves to the next IF/ELIF block.

In the ELIF blocks carry out a  a similar operation for "s", "ch", or "sh", in order to add "es".

Finally, 's' is added to all other cases using the ELSE block which traps any noun that did not fall under the IF or any of the ELIF blocks.

This last part of the code prints both list side by side and passes them to a new list result which is printed to the screen

result = []

   for i in text:

       for j in new:

           if new.index(j) == text.index(i):

               result.append( (i,j) )

           

           

   print(result)

I called the function and passed the string you provided in your question and attached the result of the code.

Wow the answer was a on e dgenuity, ignore the other autistic answers 

Solution: the categorization of functional and non-functional requirement are as follows: some of the more typical functional requirements include: • business rules• transaction corrections, adjustments and cancellations• administrative functions• authentication• authorization levels• audit tracking• external interfaces• certification requirements• reporting requirements• historical data• legal or regulatory requirementswhile,some typical non-functional requirements are: • performance – for example response time, throughput, utilization, static volumetric• scalability• capacity• availability• reliability• recoverability• maintainability• serviceability• security• regulatory• manageability• environmental• data integrity• usability• interoperability