subject

Assume that the timeout values for all three protocols
are sufficiently long such that 5 consecutive data segments and their corresponding acks can be
received (if not lost in the channel) by the receiving host (b) and the sending host (a) respectively.
suppose host a sends 5 data segments to host b, and the second segment (sent from a) is lost. in the
end, all 5 data segments have been correctly received by host b.
(a) how many segments has host a sent in total and how many acks has host b sent in total? what
are their sequence number? answer this question for all three protocols.
(b) if the timeout values for all three protocols are much longer than 5 rtt, then which protocol
successfully delivers all five data segments in the shortest time interval?

ansver
Answers: 3

Another question on Computers and Technology

question
Computers and Technology, 22.06.2019 23:00
Is an attack that relies on guessing the isns of tcp packets
Answers: 2
question
Computers and Technology, 23.06.2019 02:50
Define a class named movie. include private fields for the title,year, and name of the director. include three public functions withprototypes void movie: : settitle(cstring); , voidmovie: : setyear(int); , void movie: : setdirector(string); . includeanother function that displays all the information about a movie.write a main() function that declares a movie object namedmyfavoritemovie. set and display the object's fields.this is what i have but know its wrong since it will notcompile: #include#includeusing namespace std; //class declarationclass movie{private: string movietitle ; string movieyear; string directorname; public: void settitle(string title); void setyear(string year); void setdirector(string director); void displayinfo(); }; //class implementationvoid movie: : settitle(string title){ movietitle = title; cout< < "what is the title of themovie? "< > temp; myfavoritemovie.settitle(temp); cout< < "enter movie year"< > temp; myfavoritemovie.setyear(temp); cout< < "enter director'sname"< > temp; myfavoritemovie.setdirector(temp); //display all the data myfavoritemovie.displayinfo(); system("pause"); return 0; this code is not entirely mine someone on cramster edited my firstcode but then i try manipulating the new code and i still get acompile error message : \documents\visual studio 2008\projects\movie\movie\movie.cpp(46) : error c2679: binary '< < ' : no operator found which takes aright-hand operand of type 'std: : string' (or there is no acceptableconversion)c: \program files (x86)\microsoft visual studio9.0\vc\include\ostream(653): could be'std: : basic_ostream< _elem,_traits> & std: : operator< < > (std: : basic_ostream< _elem,_traits> & ,const char *)w
Answers: 1
question
Computers and Technology, 23.06.2019 11:30
In cell h5 enter a formula that will calculate the percentage of attendees that went to the altamonte springs job fair in 2018.
Answers: 1
question
Computers and Technology, 23.06.2019 18:30
This program should be a short piece of code that prints all of the positive integers from 1 to 100 as described more fully below. the program may contain multiple methods, and if using an oo language, should be contained within a single class or object. the program should be designed so that it begins execution when invoked through whichever mechanism is most common for the implementation language. â–ş print out all positive integers from 1 to 100, inclusive and in order. â–ş print messages to standard output, matching the sample output below. â–ş in the output, state whether the each integer is 'odd' or 'even' in the output. â–ş if the number is divisible by three, instead of stating that the number is odd or even, state that the number is 'divisible by three'. â–ş if the number is divisible by both two and three, instead of saying that the number is odd, even or divisible by three; state that the number is 'divisible by two and three'. â–ş design the logic of the loop to be as efficient as possible, using the minimal number of operations to perform the required logic. sample output the number '1' is odd. the number '2' is even. the number '3' is divisible by three. the number '6' is divisible by two and three.
Answers: 1
You know the right answer?
Assume that the timeout values for all three protocols
are sufficiently long such that 5 conse...
Questions
question
Geography, 03.12.2020 23:50
question
English, 03.12.2020 23:50
question
Mathematics, 03.12.2020 23:50
question
Mathematics, 03.12.2020 23:50
Questions on the website: 13722363