Consider the following sequence of expressions: animals = { 'a': ['aardvark'], 'b': ['baboon'], 'c': ['coati']} animals['d'] = ['donkey'] animals['d'].append('dog') animals['d'].append('dingo') we want to write some simple procedures that work on dictionaries to return information. first, write a procedure, called how_many, which returns the sum of the number of values associated with a dictionary. for example: > > > print(how_many(animals)) 6

Write a function so that the main0 code below can be replaced by the simpler code that calls function mphandminutes tomiles0. original main0 int main) l double milesperhour-70.0; double minutestraveled = 100.0; double hourstraveled; double milestraveled; hourstraveled = minutestraveled / 60.0; milestraveled = hourstraveled * milesperhour; cout < "miles" 2 using namespace std; 4 /* your solution goes here/ 6 int maino 1 test passed 7 double milesperhour 70.0 all tests passed 8 double minutestraveled 100.0; 10 cout < < "miles: " < < mphandminutestomiles(milesper-hour, minutestraveled) < < endl; 12 return 0; 13