What is the downside of wider channel bandwidth?

Suppose we have a byte addressable computer that has a 32-byte cache with 8 bytes per block. the memory address is 8 bits long. the system accesses memory addresses (in hex) in this exact order: 6e, b9, 17, e0, 4e, 4f, 50, 91, a8, ab, ad, 93, and 94. (a) assuming the cache is direct mapped, what memory addresses will be in cache block 2 after the last address has been accessed? (b) assuming the cache is direct mapped, what is the hit ratio for the entire memory reference sequence given, assuming the cache is initially empty? (c) assuming the cache is 2-way set associative with a lru replacement policy, what is the hit ratio?

Write a method named addall that could be placed inside the hashintset class. this method accepts another hashintset as a parameter and adds all elements from that set into the current set, if they are not already present. for example, if a set s1 contains [1, 2, 3] and another set s2 contains [1, 7, 3, 9], the call of s1.addall(s2); would change s1 to store [1, 2, 3, 7, 9] in some order. you are allowed to call methods on your set and/or the other set. do not modify the set passed in. this method should run in o(n) time where n is the number of elements in the parameter set passed in.

If you embed a word table into powerpoint, what happens when you make edits to the embedded data? a. edits made to embedded data change the data in the source file; however, edits made to the source file will not be reflected in the embedded data. b. edits made to embedded data will change the data in the source file, and edits made to the source file will be reflected in the embedded data. c. edits made to embedded data don't change the data in the source file, nor will edits made to the source file be reflected in the embedded data. d. edits made to embedded data don't change the data in the source file; however, edits made to the source file will be reflected in the embedded data.