Write a program that asks the user to enter five different, integer numbers. the program then reports the largest number and the smallest number.
use the if statement, but no loops.

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables

  int minn=INT_MAX;

   int maxx=INT_MIN;

   int n1,n2,n3,n4,n5;

   cout<<"enter five Numbers:";

   //read 5 Numbers

   cin>>n1>>n2>>n3>>n4>>n5;

   // find maximum

   if(n1>maxx)

    maxx=n1;

    if(n2>maxx)

    maxx=n2;

    if(n3>maxx)

    maxx=n3;

    if(n4>maxx)

    maxx=n4;

    if(n5>maxx)

    maxx=n5;

   // find minimum

   if(n1<minn)

    minn=n1;

    if(n2<minn)

    minn=n2;

    if(n3<minn)

    minn=n3;

    if(n4<minn)

    minn=n4;

    if(n5<minn)

    minn=n5;

   // print maximum and minimum

   cout<<"maximum of five numbers is: "<<maxx<<endl;

   cout<<"minimum of five numbers is: "<<minn<<endl;

return 0;

}

Explanation:

Declare two variables "minn" & "maxx" and initialize them with INT_MAX and INT_MIN respectively.Then read the five number from user and compare it with "minn" & "maxx" ,if input is greater than "maxx" then update "maxx" or if input is less than "minn" then update the "minn". After all the inputs, "minn" will have smallest and "maxx" will have largest value.

enter five Numbers:5 78 43 55 12

maximum of five numbers is: 78

minimum of five numbers is: 5

hey there! :

mass = 5.75 g

volume = 7.5 cm³

therefore:

density = mass / volume

d = 5.75 / 7.5

d = 0.7 g/cm³

answer c

hope that !

answer; i do believe that the correct answer is : a deadly factory fire;