C++ 2.30 lab: phone number breakdown given a long long integer representing a 10-digit phone number, output the area code, prefix, and line number, separated by hyphens. ex: if the input is: 8005551212 the output is: 800-555-1212 hint: use % to get the desired rightmost digits. ex: the rightmost 2 digits of 572 is gotten by 572 % 100, which is 72. hint: use / to shift right by the desired amount. ex: shifting 572 right by 2 digits is done by 572 / 100, which yields 5. (recall integer division discards the fraction). for simplicity, assume any part starts with a non-zero digit. so 999-011- is not allowed. lab

My mom and i are moving and we don’t have wifi for the next week, i want to know if using a using a hotspot with unlimited data is better than using regular wifi. i’m considering cost, speed, and data sacrifices.

This program should be a short piece of code that prints all of the positive integers from 1 to 100 as described more fully below. the program may contain multiple methods, and if using an oo language, should be contained within a single class or object. the program should be designed so that it begins execution when invoked through whichever mechanism is most common for the implementation language. â–ş print out all positive integers from 1 to 100, inclusive and in order. â–ş print messages to standard output, matching the sample output below. â–ş in the output, state whether the each integer is 'odd' or 'even' in the output. â–ş if the number is divisible by three, instead of stating that the number is odd or even, state that the number is 'divisible by three'. â–ş if the number is divisible by both two and three, instead of saying that the number is odd, even or divisible by three; state that the number is 'divisible by two and three'. â–ş design the logic of the loop to be as efficient as possible, using the minimal number of operations to perform the required logic. sample output the number '1' is odd. the number '2' is even. the number '3' is divisible by three. the number '6' is divisible by two and three.

4. does the kernel phenotype distribution support the idea that the cob is the result of a dihybrid cross? what information supports your answer? if a dihybrid cross (i.e. f1 to f2 of standard mendelian crosses) is not indicated what conditions might contribute to this finding.