What is the output of the following program when the method is called with 4?
void unknown(int n)
{
if(n> 0)
{
system. out. print("? ");
unkown(n-1);
}
}
a. none of the other answers

A.

Explanation:

void unknown(int n) defines a methodes that doesn't return a value, hence unknow(int n) is a function... it is function that prints the value ? as many times as you tell it, hence for n=4 it would print . However, it doesn't return a value an interger, string etc..., so it doesn't give an output .  

answer; i believe that the correct answer is (a)

yes the ansewer is c bc you can look it up!