Problem 1 - hashing we would like to use initials to locate an individual. for instance, mel should locate the person mark e. lehr. note: this is all upper case. generate a hash function for the above using the numbers on your telephone. you know, each letter has a number associated with it, so examine your telephone keypad. generate 512 random 3 letter initials and take statistics on a linked list array size 512 to hold this information report how many have no elements, 1 element, 2 elements, does this agree with the hashing statistics distribution?

Assume that you have an sorted array of records. assume that the length of the array (n) is known. give two different methods to search for a specific value in this array. you can use english or pseudo-code for your algorithm. what is the time complexity for each algorithm and why?

What is the original authority for copyright laws

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }