Import java. util. scanner; public class sumofmax { public double findmax(double num1, double num2) { double maxval; // note: if-else statements need not be understood to // complete this activity if (num1 > num2) { // if num1 is greater than num2, maxval = num1; // then num1 is the maxval. } else { // otherwise, maxval = num2; // num2 is the maxval. } return maxval; } public static void main(string [] args) { double numa = 5.0; double numb = 10.0; double numy = 3.0; double numz = 7.0; double maxsum = 0.0;

Here you go,

Import java.util.scanner

public class SumOfMax {

   public static double findMax(double num1, double num2) {

       double maxVal = 0.0;

       // Note: if-else statements need not be understood to

       // complete this activity

       if (num1 > num2) { // if num1 is greater than num2,

           maxVal = num1; // then num1 is the maxVal.

       }

       else { // Otherwise,

           maxVal = num2; // num2 is the maxVal.

       }

       return maxVal;

   }

   public static void main(String[] args) {

       double numA = 5.0;

       double numB = 10.0;

       double numY = 3.0;

       double numZ = 7.0;

       double maxSum = 0.0;

       /* Your solution goes here */

       maxSum = findMax(numA, numB); // first call of findMax

       maxSum = maxSum + findMax(numY, numZ); // second call

       System.out.print("maxSum is: " + maxSum);

       return;

   }

}

/*

Output:

maxSum is: 17.0

*/

answer; i think/believe the correct answer is balance sheet;

answer; its the top layer;