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Swiping and pinching are graphical user interface (gui)

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Computers and Technology, 22.06.2019 10:40
"it security policy enforcement and monitoring" respond to the following: describe how monitoring worker activities can increase the security within organizations. describe the rationale that managers should use to determine the degree of monitoring that the organization should conduct. explain the extent to which you believe an organization has the right to monitor user actions and traffic. determine the actions organizations can take to mitigate the potential issues associated with monitoring user actions and traffic.
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Computers and Technology, 22.06.2019 20:00
What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }
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Computers and Technology, 23.06.2019 01:20
Me with this program in c++ ! computers represent color by combining sub-colors red, green, and blue (rgb). each sub-color's value can range from 0 to 255. thus (255, 0, 0) is bright red. (130, 0, 130) is a medium purple. (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (in other word, equal amounts of red, green, blue yield gray).given values for red, green, and blue, remove the gray part. ex: if the input is 130 50 130, the output is: 80 0 80. thus, find the smallest value, and then subtract it from all three values, thus removing the gray.
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Computers and Technology, 23.06.2019 01:40
Writing a modular program in visual c++. i am new to this and not sure what i am missing. i am getting the following error: baddate.cpp: in function ‘int main()’: baddate.cpp: 50: 3: error: ‘else’ without a previous ‘if’elsehere are the instructions and code: writing a modular program in c++in this lab, you add the input and output statements to a partially completed c++ program. when completed, the user should be able to enter a year, a month, and a day. the program then determines if the date is valid. valid years are those that are greater than 0, valid months include the values 1 through 12, and valid days include the values 1 through 31.notice that variables have been declared for you.write the simulated housekeeping() function that contains the prompts and input statements to retrieve a year, a month, and a day from the user.include the output statements in the simulated endofjob() function. the format of the output is as follows: month/day/year is a valid date.ormonth/day/year is an invalid date.execute the program entering the following date: month = 5, day = 32, year = 2014. record the output of this program.execute the program entering the following date: month = 9, day = 21, year = 2002. record the output of this /* program name: baddate.cppfunction: this program determines if a date entered by the user is valid.input: interactiveoutput: valid date is printed or user is alerted that an invalid date was entered*/#include bool validatedate(int, int, int); using namespace std; int main(){// declare variablesint year; int month; int day; const int min_year = 0, min_month = 1, max_month = 12, min_day = 1, max_day = 31; bool validdate = true; // this is the work of the housekeeping() method// get the year, then the month, then the daycout< < "enter the year"< > year; cout< < "enter the month"< > month; cout< < "enter the day"< > day; // this is the work of the detailloop() method// check to be sure date is validif(year < = min_year) // invalid yearvaliddate = false; else if (month < min_month || month > max_month) // invalid monthvaliddate = false; else if (day < min_day || day > max_day) // invalid dayvaliddate = false; // this is the work of the endofjob() method// test to see if date is valid and output date and whether it is valid or notif(validdate == true); {// output statementcout<
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