Acompound x of molecular formula c8h12 with no triple bonds reacts with one equivalent of h2 to give a new compound having molecular formula c8h14. what can be inferred about the structure of compound x?

The molecular formula given is C₈H₁₂, and it is also stated that it does not contain any triple bond and reacts with one equivalent H₂ to give a new compound with molecular formula C₈H₁₄.

First let us find the HDI (Hydrogen Deficiency Index) of this compound.

                                  HDI  =  2C + 2 + N - H - X / 2
So,
                                  HDI  =  2(8) + 2 - 12 / 2

                                  HDI  =  16 + 2 -12 / 2

                                  HDI  =  6 / 2

                                  HDI  =  3

Hence HDI 3 means, that our structure may contain following

                            1)  3 double bonds

                            2)  1 double bond and 1 triple bond

                            3)  3 Rings

                            4)  2 Rings and 1 double bond

                            5)  1 Ring and 2 double bonds

Hence, there are many possible isomers. But in statement it is given that it reacts with 1 equivalent H₂, means it contains only one double bond. So, according to my opinion our structure would contain 1 double bond and two rings as we are told in start that there is no triple bond. Hence, the possible structure is as follow along with reaction with 1 equivalent H₂.