Chemistry, 21.07.2019 19:00 milkshakegrande101

Ammonium nitrite undergoes decomposition to produce only gases as shown below. nh4no2(s) → n2(g) + 2h2o(g) how many liters of gas will be produced by the decomposition of 32.0 g of nh4no2 at 525°c and 1.5 atm?

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From the given balanced reaction equation:

we can see that every 1 mole of NH4NO2 will produce 1 mole of N2 and when the water also on the gas phase so, every 1 mole of NH4NO2 will produce 3 moles of gas

now we need to get number of moles of NH4NO2 = mass/molar mass
when the mass = 32 g and the molar mass of NH4NO2 = 64 mol/g

∴moles of NH4NO2 = 32 g / 64 mol/g = 0.5 mole

so, the moles that produced of gas will be = 3 * 0.5 = 1.5 moles

now, we can use the ideal gas formula to get V:

PV = nRT

when P is the pressure = 1.5 atm

n is the number of moles = 1.5 moles

R is the ideal gas constant = 0.0821 L*atm/mol*K

and T is the temperature in Kelvin = 525 °C + 273 = 798 K

so by substitution:

1.5 atm * V = 1.5 moles * 0.0821 * 798 K

∴ V = 65.5 L

Answer from: Quest

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Can someone me with this chemical reactions worksheet

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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Ammonium nitrite undergoes decomposition to produce only gases as shown below. nh4no2(s) → n2(g) + 2...

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