Write a nuclear reaction for the neutron-induced fission of u? 235 to produce te? 137 and zr? 97. how many neutrons are produced in the reaction?

This is a neutron induced fission, therefore a neutron will be added to the U²³⁵ to cause the reaction, and thus it will be added to the left side. There will be unknown number of neutrons produced and thus we put this on the right hand side.
n₁ + U²³⁵ = Te¹³⁷ + Zr ⁹⁷ + xn1 ( n1 to mean a neutron of mass 1)
To balance the masses on both sides of the equation;
1 + 235 = 137 +97+ x
x = 2 
the end reaction will be
n₁ +U²³⁵ = Te¹³⁷ + Zr⁹⁷ + 2 n₁

This is a neutron induced fission, therefore a neutron will be added to the U²³⁵ to cause the reaction, and thus it will be added to the left side. There will be unknown number of neutrons produced and thus we put this on the right hand side.n₁ + U²³⁵ = Te¹³⁷ + Zr ⁹⁷ + xn1 ( n1 to mean a neutron of mass 1)To balance the masses on both sides of the equation;1 + 235 = 137 +97+ xx = 2 the end reaction will ben₁ +U²³⁵ = Te¹³⁷ + Zr⁹⁷ + 2 n₁

The answer is probably c. xylem