Element z has two natural isotopes: z-79 (78.918 amu) and z-81 (80.916 amu). calculate the atomic mass of element z given the abundance of z-81 is 49.31%.

Isotopes are atoms of the same element with different number of neutrons, hence different mass numbers.
relative atomic mass is the weighted average atomic masses of the isotopes.
atomic mass of element z =78.918 amu x (100-49.31)%+ 80.916 amu x 49.31%
 atomic mass = (78.918 x 50.69%) + (80.916 x 49.31%)
                      = 40.00 + 39.90 
 atomic mass of element z = 79.90 

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !