A50.0 ml sample of ca(oh) 2 is neutralized by 300.0 ml of hcl solution with a ph of 1.3. calculate the molarity of the ca(oh) 2 solution. 1. 0.50 m 2. 1.0 m 3. 0.05 m 4. 0.30 m 5. 0.15 m

The  molarity  of  the Ca(OH)2   solution  is calculated as  follows

find the  concentration  of HCl  used   from  the Ph
that  is PH =  -  log  H+= 1.3

H+ =   10^-1.3  = 0.05 M
the moles  of HCl = molarity  x  volume/1000
= 0.05  x 300/1000=0.015 moles

write  the reaction equation

that is Ca(OH)2 +2HCl=CaCl2  +  2H20
by  use  of reacting ratio   between  Ca(OH)2  to  HCl (1:2)   the  moles  of  Ca(OH)2  is =  0.015 x1/2=7.5  x10^-3  moles

molarity is  therefore =  moles /volume  in  liters

= {( 7.5x10^-3) /50}  x1000  =  0.15 M (  answer  5)
 

Not a  mixture of two common elements that can be separated by physical means.

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