What is the mass of water required to prepare 250.0 g of 10.0% copper(ii) sulfate solution?

mass of water is 225g

Explanation:

What is the mass of water required to prepare 250.0 g of 10.0% copper(ii) sulfate solution?

Note:mass is the quantity of water in a body.

The question is asking us to look for the amount of water in the solution that contains 10% of copper (ii) sulphate vi by mass

percentage concentration by mass=mass of solute/mass of solution*100%

c%=

aslo

mass of solution=mass of solute+mass of solvent

the solvent in this case is water

the solute is copper (ii) tetraoxosulphate (vi)

10%=mass of solute/250*100%

mass of solute=25g

250g=25g+mass of solvent

mass of solvent=250-25

mass of solvent=225g

mass of water is 225g

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.