Determine the celsius temperature of 2.08 moles of gas contained in a 1.00 l vessel at a pressure of 177 kpa. -183 incorrect: your answer is incorrect. °c

We can use the ideal gas law equation to find the temperature,
PV = nRT
where
P - pressure - 177 kPa
V - volume 1.00 x 10⁻³ m³
n - number of moles -  2.08 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature 
substituting these values in the equation
177 x 10³ Pa x 1.00 x 10⁻³ m³ = 2.08 mol x 8.314 Jmol⁻¹K⁻¹ x T
T = 10.2 K
temperature in celsius - 10.2 -273 = - 262.8 °C