How many liters of h2 would be formed at 684 mm hg and 13 ∘c if 21.0 g of zinc was allowed to react?

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

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