What is the volume of 0.110 g of c2h2f4 vapor at 0.575 atm and 34.8◦c? answer in units of l?

To calculate the volume of the gas, we can use the ideal gas law equation.
PV = nRT
P - pressure - 0.575 atm x 101 325 Pa/atm = 58 261.9 Pa
V - volume 
n - number of moles 
C₂H₂F₄ - molar mass - 102 g/mol
Number of moles - 0.110 g / 102 g/mol = 0.00108 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 34.8 °C + 273 = 307.8 K
Substituting values in the equation,
58 261.9 Pa x V = 0.00108 mol x 8.314 Jmol⁻¹K⁻¹ x 307.8 K
V = 0.0000474 m³
V = 0.0474 L

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