Answers: 1
and solubility in grams per liter is 
gives 1 mole of 
and 1 mole of 
.![K_sp=[Ag^+][I^-]](/tpl/images/0128/0319/f6f6c.png)
![8.3\times 10^{-17}=[s][s]](/tpl/images/0128/0319/983c8.png)
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Calculate the molar solubility and the solubility in g / l of agi at 25°c. the ksp of agi is 8.3 × 1...
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