Chemistry, 24.07.2019 21:00 haileysolis5

Consider the compound sn(so4)2 and answer the following questions: a. what is the name of this compound? b. what is the molar mass of this compound? explain how you calculated this value.

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A. This compound is Tin(IV) Sulfate, or Stannic Sulfate. It depends on which naming methodology you are using, but both are correct.

B. The molar mass of this compound is calculated by the combination of the formula weights of all the pieces of the compound, so you need to add the weights of

Sn+2S+8O
118.7 + 2(32.07) + 8(15.99)
118.7 + 64.14 + 127.92
310.76

The molar mass is 310.76 g/mol.

Answer from: milkshakegrande101

Answer :

(a) The name of Sn(SO_4)_2 compound is, tin sulfate.

(b) The molar mass of Sn(SO_4)_2 is 310.83 g/mol

Explanation :

(a) As we know that the tin is the alkali metal having the atomic number 50 and belongs to group 14. The symbol of tin is, (Sn). The stable oxidation state of strontium is (+4).

The element sulfate is the non-metal polyatomic ion. The stable oxidation state of sulfate ion $(SO_4^{2-})$ is, (-2).

When the tin combine with the sulfate ion, it forms tin sulfate. It is an ionic compound in which the a metal react with the non-metal and combine with the an ionic bond by the criss-cross method.

The formula of the tin sulfate is, Sn(SO_4)_2

Hence, the name of Sn(SO_4)_2 compound is, tin sulfate.

(b) Now we have to determine the molar mass of Sn(SO_4)_2 .

Molar mass : It is defined as the mass in grams of one mole of substance and each element has its own unique molar mass. It is expressed in grams/mole or g/mol. It is equal to the mass of atom present in 1 mole.

As we know that,

Molar mass of 'Sn' = 118.71 g

Molar mass of 'S' = 32.066 g

Molar mass of 'O' = 15.999 g

Molar mass of Sn(SO_4)_2 = 118.71+2(32.066)+8(15.999)

Molar mass of Sn(SO_4)_2 = 310.83 g

Hence, the molar mass of Sn(SO_4)_2 is 310.83 g/mol

Answer from: Quest

Engineers have contribute to society in many ways like making the technology we use today or any type of power energy material

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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