What is the order in which electrons start filling the orbitals? a: 1s 2s 2p 3s 3p 4s 3d 4p b: 1s 2s 2p 3s 3p 3d 4s 4p c: 1s 2s 2p 3s 4s 3p 3d 4p d: 1s 2s 2p 3s 4s 4p 3p 3d e: 1s 2s 2p 3s 4s 3p 4p 3d

The answer is actually A, 1s 2s 2p 3s 3p 4s 3d 4p.

The correct answer is option A, that is, 1s 2s 2p 3s 3p 4s 3d 4p.

Explanation:

In quantum chemistry and atomic physics, the distribution of electrons of a molecule or an atom in atomic or molecular orbitals is known as the electronic configuration. The electronic configurations illustrate each electron as moving autonomously in an orbital. Mathematically, the configurations are illustrated by configuration state functions or Slater determinants. The electron starts filling the orbitals in an order 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 7s 5f 6d and 7p.

a. a clone will be physically identical to the original, but won’t be genetically identical

have a good day!

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j