In the compound k[co(c2o4)2(h2o)2] (where c2o42– = oxalate) the oxidation number and coordination number of cobalt are, respectively

Oxidation number: 3+

Coordination number: 4

Explanation:

In the compound K[Co(C₂O₄)₂(H₂O)₂] (where C₂O₄²⁻ = oxalate) the oxidation number and coordination number of Cobalt are, respectively?

The sum of the oxidation numbers and charges of the species forming the complex is equal to the overall charge, in this case, zero.

K + Co + 2 . C₂O₄²⁻ + 2 . H₂O = 0

+1 + Co + 2 . (2-) + 2 . 0 = 0

Co = 3+

The coordination number is the number of ligands attached to the central atom. 2 oxalates and 2 water molecules are attached to the cobalt atom, so the coordination number is 2 +2 = 4.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be