Chemistry, 25.07.2019 14:00 ecoagro1934
A52.0-ml volume of 0.35 m ch3cooh (ka=1.8×10−5) is titrated with 0.40 m naoh. calculate the ph after the addition of 27.0 ml of naoh. express your answer numerically.
Answers: 1
and 
.
![[H^+]=\frac{\text{Moles of }H^+}{\text{Total volume}}](/tpl/images/0131/3396/b6338.png)
![[H^+]=\frac{0.0007mole}{(52+27)mL}=8.9\times 10^{-6}mole/mL=8.9\times 10^{-3}M](/tpl/images/0131/3396/73338.png)
![pH=-\log [H^+]](/tpl/images/0131/3396/37e81.png)
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A52.0-ml volume of 0.35 m ch3cooh (ka=1.8×10−5) is titrated with 0.40 m naoh. calculate the ph after...
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