Chemistry, 25.07.2019 16:00 smarcalli6457
What are the concentrations of oh– and h in a 0.00043 m solution of ba(oh)2 at 25 °c? assume complete dissociation?
Answers: 1
![[OH^-]=0.00086\frac{molOH}{L}](/tpl/images/0131/6875/3f79e.png)
![[H^+]=1.16x10^{-11}\frac{molH^+}{L}](/tpl/images/0131/6875/a68ba.png)
via:![[OH^-]=0.00043\frac{molBa(OH)_2}{L} *\frac{2molOH^-}{1molBa(OH)_2} =0.00086\frac{molOH}{L}](/tpl/images/0131/6875/d05e1.png)
![Kw=[H^+][OH^-]\\H^+=\frac{Kw}{[OH^-]}=\frac{1x10^{-14}}{0.00086} =1.16x10^{-11}\frac{molH^+}{L}](/tpl/images/0131/6875/67910.png)
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What are the concentrations of oh– and h in a 0.00043 m solution of ba(oh)2 at 25 °c? assume comple...
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