Is the aqueous solution of each of these salts acidic, basic, or neutral? (a) cr(no3)3 acidic basic neutral (b) nahs acidic basic neutral (c) zn(ch3coo)2 acidic basic neutral?

(a) Neutral.

(b) Basic.

(c) Basic.

Explanation:

Hello,

In this case, we must take a look of both the cation's and anion's nature, it means, if they come from a strong or weak acid or base, thus:

(a) Chromium (III) hydroxide is a strong base and nitric acid is a strong acid, consequently, chromium (III) nitrate is a neutral base since every ion is neutralized.

(b) Sodium hydroxide is a strong base and the hydrosulfuric acid is a weak acid, so there will be unreacted OH- ions, consequently, sodium hydrosulfide is a basic salt.

(c) Zinc hydroxide is a strong base and acetic acid is a weak acid, therefore, as in the previous salt, this is a basic salt.

Best regards.

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol