Calculate the percent yield in the photosynthesis in reaction by which carbon dioxide is converted to sugar if 7.03 grams of carbon dioxide yield 3.92 grams of c6h1206.

The balanced reaction for photosynthesis is as follows;
6CO₂ + 6H₂O --> C₆H₁₂O₆  + 6O₂
stoichiometry of CO₂ to  C₆H₁₂O₆ is 6:1
Number of moles of CO₂ reacted - 7.03 g/ 44 g/mol = 0.16 mol
number of C₆H₁₂O₆ moles formed - 0.16 mol / 6 = 0.027 mol
Mass of C₆H₁₂O₆ formed - 0.027 mol x 180 g/mol = 4.86 g
Actual yield of C₆H₁₂O₆ - 3.92 g
percent yield of C₆H₁₂O₆ = actual yield / theoretical yield x 100%
                                      = 3.92 g/ 4.86 g x 100% 
percent yield = 80.7%

Dsolubility let me know if you have any other questions for chemistry