Acompound contains potassium, nitrogen, and oxygen. the experimental analysis gave values of 45.942 % potassium and 16.458 % nitrogen, by weight, the remainder is oxygen. what is the empirical formula of the compound?

KNO₂

Explanation:

To get the empirical formula of a compound, we follow a series of steps.

Step 1: Given data

%K = 45.942%

%N = 16.458%

%O = 100.000% - 45.942% - 16.458% = 37.600%

Step 2: Divide each percentage by the atomic mass of the element

K: 45.942 / 39.098 = 1.1750

N: 16.458 / 14.007 = 1.1750

O: 37.600 / 15.999 = 2.3501

Step 3: We divide all the coefficients by the smallest number

K: 1.1750 / 1.1750 = 1

N: 1.1750 / 1.1750 = 1

O: 2.3501 / 1.1750 = 2

The empirical formula is KNO₂.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

d.) circle motion requires a force to give it a centripetal acceleration.