Part a (7 points): how many grams of iron (fe) will be produced if you start with 3.65 liters of carbon monoxide gas (co) at stp? fe2o3 + 3 co --> 2 fe + 3 co2 part b (3 points): jacob performed the above experiment in his chemistry class, and collected 4.23 grams of iron. what is the percent yield?

The balanced chemical equation for the above reaction is as follows;
Fe₂O₃ +  3CO --> 2 Fe + 3 CO₂
stoichiometry of CO to Fe produced is 3:2
Molar volume is where 1 mol of any gas occupies a volume of 22.4 L 
If 22.4 L contains 1 mol of CO
then 3.65 L contains - 1/22.4 x 3.65 = 0.16 mol 
the number of CO moles reacting - 0.16 mol
If 3 mol of CO produces 2 mol of Fe
then 0.16 mol of CO produces - 2/3 x 0.16 = 0.106 mol
mass of Fe produced - 0.106 mol x 55.8 g/mol = 5.91 g

B)
the theoretical yield of Fe, when 0.16 mol of CO reacts - 5.91 g
however the actual yield - 4.23 g 
to find the percent yield = actual yield /theoretical yield x 100 %
percent yield of Fe - 4.23 / 5.91 x 100% = 71.6%