Describe how a sample of copper chloride crystals could be made from copper carbonate and dilute hydrochloric acid

Copper carbonate neutralises the hydrochloric acid 

test formation method:- 
1  put 25 ml 1M acid in beaker warm gently don't boil  ( remove from heat )
2 Add the green copper carbonate powder slowly . because co2 is quickly evovled. now stir mixture 
3  Continue adding powder until traces of unreacted carbonate left at bottom of beaker
4  now separate unreacted solid from green solution by filtration .
5  pour it in evapourating dish . heat over a water bath to make solution more clear 
[ you can test it by dipping in a glass rod abd check if crystal form , if they formed cover the dish with piece of filter paper and let solution crystalline naturally ]

{chemical reaction of this all is attached below}

Hbr dissociates to form h+ and br-ca(oh)2 dissociates to form ca2+ and 2oh-the h+ and oh- react to form waterassuming the reactants are dissolved in water, the net reaction is h+ + oh- —> h2oif you’re asked to show all components of the reaction, the complete reaction is 2hbr + ca(oh)2 —> cabr2 + 2h2o

Hope you find the answer