Chemistry, 27.07.2019 14:30 lychee1406

In a popular demonstration, vinegar and baking soda are combined in a bottle as shown. sodium carbonate, water, and carbon dioxide gas are formed. the balloon traps the carbon dioxide. if the bottle were left open with no balloon, predict which outcome is most likely. a) all substances would still be in the bottle. b) the surrounding air would have less carbon dioxide. c) the mass of the reactants would be less than the mass of the products. d) the mass of the products would be less than the mass of the reactants.

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A is incorrect because, the carbon dioxide is being pushed up by the below mixture of baking soda and vinegar.

B is incorrect because the carbon dioxide gets pushed out of the bottle and joins the air around the bottle, adding carbon dioxide to the air around the bottle.

C is incorrect because the mass of the reactants, the baking soda and vinegar, is more then the carbon dioxide it creates.

D is correct because the mass of the reactants is more then the carbon dioxide it creates.

I hope this helps you. please mark brainliest, thank you :)

Answer from: guapotaco8102

Option (D) is the correct answer.

Explanation:

If the bottle were left open with no balloon, the all the carbon dioxide will go into the surrounding.

This means that now the products will only be sodium carbonate and water. As we known that law of conservation of mass states that mass can neither be created nor it can be destroyed. But it can be transformed from one form to another.

Since, $CO_{2}$ escapes into the surrounding. Hence, there will occur a decrease in the mass of products as compared to the mass of reactants.

Thus, we can conclude that if the bottle were left open with no balloon, then mass of the products would be less than the mass of the reactants, is most likely to be outcome.

Answer from: Quest

b i think it’s a water wheel turning in a stream

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