Chemistry, 28.07.2019 18:00 EmTerrell2933
Calculate the ph of a solution that is 0.245m benzoic acid and 0.170m sodium benzoate, a salt whose anion is the conjugate base of benzoic acid.
Answers: 1
![pH=pKa + log( \frac{ [A^{-}]}{[HA]} ) \\ \\ pH=4,20 + log ( \frac{0,170 M}{0,245} ) \\ \\ pH=4,04](/tpl/images/0143/7061/63415.png)
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Calculate the ph of a solution that is 0.245m benzoic acid and 0.170m sodium benzoate, a salt whose...
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