Ammonia is often formed by reacting nitrogen and hydrogen gases. how many liters of ammonia gas can be formed from 22.7 l of hydrogen gas at 93.0°c and a pressure of 49.6 kpa?

Nitrogen  +  hydrogen =   ammonia

N2  + 3  H2  --->  2  NH3

from  ideal  gas   equation  that  is  pv  =nRT where  p  is  pressure, v=  volume,   n= number  of  moles,R = gas  constant  and  t=  temperature
   
from  information  above in  the   question
P=  49.6  kpa
V=22.7 L
t =93 +273=366 K
R=8.314  l.Kpa /mol
n=?
from  ideal  gas  equation  n= Pv/RT
n=  (49.6  x22.7)  /(  8.314  x 366)  =  0.37  moles  of  nitrogen

by   use  of  moles ratio  between  N2   to   NH3  from  equation  above   which   is  3:2  therefore  moles  of   NH3  =   0.37  x2/3=  0.247  moles  of  Nh3
1mole  of  ideal  gas  =  22.4  L   at   stp
what  about   0.247  moles
 ( 0.247  x22.4)/  1=  5.53  liters   of  ammonia