What is the molality of a 10.5% by mass glucose (c6h12o6) the density of the solution is 1.03 g/ml. i got up to m = 0.058281527 mol/,

Solution:
1 L of solution and 1.03 g/mL = 1030 g/L 

1030 g/L time 10.5%
= 108.15 g of glucose/L
And
=108.15 g / 180.16 g/mol
= 0.6003 moles in 1L 
=or 0.600 mol/kg

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