Calculate the freezing point of a solution containing 15 grams of kcl and 1650.0 grams of water. the molal-freezing-point-depression constant (kf) for water is 1.86 ∘c/m

Answer : The freezing point of a solution is

Explanation :  Given,

Molal-freezing-point-depression constant for water =

Mass of KCl (solute) = 15 g

Mass of water (solvent) = 1650.0 g  = 1.650 kg

Molar mass of KCl = 74.5 g/mole

Formula used :  

where,

= change in freezing point

= freezing point of solution = ?

= freezing point of water =

i = Van't Hoff factor = 2  (for KCl electrolyte)

= freezing point constant for water =

m = molality

Now put all the given values in this formula, we get

Therefore, the freezing point of a solution is

the dissolution of polymer can be thermodynamically described in 2 steps.