Chemistry, 30.07.2019 13:30 hmock65

N2 (g) + 3h2 (g) --> 2 nh3 (g) the equation above is the equation for the haber process. in a certain reaction, you start with 3.0 moles of nitrogen and 4.0 moles of hydrogen,. how many moles of ammonia will be produced in the reaction?

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Answers

6 mol NH3.

Explanation:

1) You have to work with the balanced chemical equation, which is given:

N2(g) + 3H2 (g) → 2 NH3 (g)

2) The mole ratios are:

1 mol N2 : 3 mol H2 : 2 mol NH3

3) Determine wich reactant is limiting the reaction

3.0 moles N2
= 0.75
4.0 moles H2

Theoretical ratio:

1 mol N2
= 0.33
3 mol H2

0.33 < 0.75 means that there is less N2 than the theoretically needed to react with 4 moles of H2, so N2 is the limiting reactant.

Therefore, the 3.0 moles of N2 will react fully and you can set the proportion with that to find the amount of NH3 produced.

4) Set the proportion

2 mol NH3 x
=
1 mol N2 3 mol N2

5) Solve for x:

x = 3 mol N2 * 2 mol NH3 / 1 mol N2 = 6 mol NH3

6 mol NH3.

That is the double number of moles than the moles of N2 that react, which is what the balanced chemical equation given.

Answer from: Quest

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

Answer from: Quest

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. $hbr$ completely dissociates to $h^+$ and $br-$ ions. a is incorrect because $h_2s$ does not fully ionize to $h^+$ and $hs^-$ ions and some remain as the compound $h_2s$ . c and d are incorrect because, $li_2o$ and $libr$ do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise, if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both $li_2o$ and $libr$ have a complete octet so can not accept any electrons which disqualifies them as acids.

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N2 (g) + 3h2 (g) --> 2 nh3 (g) the equation above is the equation for the haber process. in a cer...

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