Consider the balanced equation. 2hcl + mg mgcl2 + h2 if 40.0 g of hcl react with an excess of magnesium metal, what is the theoretical yield of hydrogen? 1.11 g 2.22 g 52.2 g 104 g

2Hcl  +mg--->MgCl2+ H2
The  theoretical  yield  of  hydrogen  is  calculated  as  follows
calculate  the  moles  of  Hcl
mass/molar  mass
40g/36.5=1.096  moles
by  use  of  mole  ratio  of  Hcl to  H2 which  is  2:1
moles  of  H2=1.096  /2=0.548moles
mass  is  therefore= moles  x molar  mass
that is  0.548moles  x 2  =1.096 grams