Apiece of metal weighing 5.10 g at a temperature of 48.6 c was placed in a calorimeter in 20.00 ml of water at 22.1 degrees c the final equilibrium temperature was found to be 29.2 what is teh specific heat of the metal

Heat gained is equal to the heat lost;
Heat lost by metal  = 5.10 ×y ×19.4, where y is the specific heat capacity of the metal.
                              = 98.94 y
Heat gained by water = 20 g× 4.18 j/g× 7.1
                                  = 593.56 Joules
Therefore; 98.94 y = 593.56
                            y = 593.56/98.94
                               = 5.99919 j/g
                               ≈ 6.0 j/g
Therefore, the specific heat capacity of the metal is 6.0 J/g°C

Cis your correct answer

Iwould you figure it out but you don't have a picture or in your question as to what the physical property you're looking for is