Astudent performing this experiment mistakenly used 6.0 ml of 16 m hno3 to dissolve 0.18g of solid copper , instead of the 4.0 ml described in lab manual. what volume of 6 m naoh are required to neutralized the excess acid

Hello!

The reaction for the dissolving of solid copper with HNO₃ is the following:

Cu (s) + 4HNO₃ (aq) → Cu(NO₃)₂ (aq) + 2NO₂ (g) + 2H₂O (l)

The required mL to neutralize 0,18 g of solid copper are calculated using the following conversion factor:



Now we subtract this value to the volume of HNO3 added by the student:



To finish, we calculate the volume of NaOH 6M required to neutralize this amount of 16M acid in excess. The reaction is the following:

HNO₃ + NaOH → NaNO₃ + H₂O

To calculate this value, we use the following conversion factor:



So, you'll need 14,11 mL of 6M NaOH to neutralize the excess acid

Atomicity occurs to prevent updates of the database occurring only partially, which can cause greater problems than rejecting the whole series outright.some are monatomic, diatomic, triatomic etc because it shows the number of atoms. for example, monatomic means it contains only one atom.