Asolution is prepared by dissolving 17.75 g sulfuric acid, h2so4, in enough water to make 100.0 ml of solution. if the density of the solution is 1.1094 g/ml, what is the molality?

The molality of solution is 1.94 m.

Explanation:

We are given:

Mass of sulfuric acid = 17.75 grams

Volume of solution = 100 mL

Density of solution = 1.1094 g/mL

To calculate the mass of solution, we use the equation:

Putting values in above equation, we get:

Mass of solvent = Mass of solution - Mass of solute

Mass of solvent = 110.94 - 17.75 = 93.19 g

To calculate the molality of solution, we use the equation:

Where,

= Given mass of solute = 17.75 g

= Molar mass of solute = 98 g/mol

= Mass of solvent = 93.19 g

Putting values in above equation, we get:

Hence, the molality of solution is 1.94 m.

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