How many grams of h 2 are needed to produce 12.95 g of n h 3 ?

Answer is: mass of hydrogen is 2.28 grams.

Balanced chemical reaction: 3H₂ + N₂ → 2NH₃.

m(NH₃) = 12.95 g; mass of ammonia.

n(NH₃) = m(NH₃) ÷ M(NH₃).

n(NH₃) = 12.95 g ÷ 17.03 g/mol.

n(NH₃) = 0.76 mol; amount of ammonia.

From chemical reaction: n(H₂) : n(NH₃) = 3 : 2.

n(H₂) = 3 · 0.76 mol ÷ 2.

n(H₂) = 1.14 mol; amount of hydrogen.

m(H₂) = 1.14 mol · 2 g/mol.

m(H₂) = 2.28 g; mass of hydrogen.

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