Calculate the energy to heat the cube of silver, with a volume of 20.0 cm3 , from 15 âc to 32 âc. (assume that density of silver is 10.5 g/cm3, specific heat for silver is 0.235 j/gâc.)

Energy = mass × specific heat capacity × change in temperature...

We ain't given mass in the question but volume and density as well...

Then we can use the relationship density = mass/volume
Mass = density × volume
Mass = 10.5g/cm³ × 20cm³
Mass = 210g

Energy = 210 × 0.235 × (32-15)

Energy = 210×0.235×17

Energy = 838.95J

Or 0.84Kj

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