Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kj of heat. the bomb calorimeter has a mass of 1.20 kg and a specific heat of 3.55 j/(gi°c). if the initial temperature of the calorimeter is 22.5°c, what is its final temperature?

The final temperature of the calorimeter is 25.8 °C

From the question given above, the following data were obtained:

Q = MC(T₂ – T₁)

14000 = 1200 × 3.55(T₂ – 22.5)

14000 = 4260(T₂ – 22.5)

Clear bracket

14000 = 4260T₂ – 95850

Collect like terms

14000 + 95850 = 4260T₂

109850 = 4260T₂

Divide both side by 4260

T₂ = 109850 / 4260

T₂ = 25.8 °C

Learn more about heat transfer:

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answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.