In the chemical reaction: br2(g) + cl2(g) ↔ 2 brcl(g) kp = 0.150 if there is initially 0.500 atm of brcl and nothing else in a container, what direction does the reaction move: a) q > k and the reaction moves to the right b) q > k and the reaction moves to the left c) q < k and the reaction moves to the left d) q < k and the reaction moves to the right

We know that

Kp = Product of partial pressures of products / product of partial pressures of reactants

For given reaction

Br2(g) + Cl2(g) ↔ 2 BrCl(g)

Q = p^2BrCl / pBr2 X pCl2   [Q= reaction quotient]

now as given that there is only BrCl in the container so the pressure of BrCl will be only pressure to be accounted

Hence

Q= (0.5)^2 = 0.25

Now as Q > Kc The reaction will move in backward direction or left side or reactant side s

so answer is

Q > K and the reaction moves to the left

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.