How do you draw the structure of 5-iodo-2-methoxyhexane?

Point out the substituents and longest carbon chain to draw the structure

Explanation:

It is a substituted alkane with longest carbon chain contains 6 carbon atoms ("Hex" denotes 6 carbons and "ane" denotes alkane)

There are two substituents present here- (1) methoxy group at C-2 position and (2) iodo group at C-5 position.

Place these two substituents in main carbon chain to draw 5-iodo-2-methoxyhexane

Skeletal structure of the given compound along with numbering has been shown below

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.