While heating two different samples of water at sea level, one boils at 102°c and one boils at 99.2°c. calculate the percent error for each sample from the theoretical 100.0°c?

To find: Sample error in percent
 Solution:
 Formula:
((Experimental value-theoretical value)/theoretical value)*100
 where, theoretical value = 100°c
 and, experimental value = 102°c (sample 1) 99.2°c (sample 2)
 Sample error (in percentage) when boiling level was 102°c = ((102°c-100°c)/100°c)*100 = 2%
 Sample error (in percentage) when boiling level was 99.2°c = ((99.2°c-100°c)/100°c)*100 = -0.8%

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