The following table lists molar concentrations of seven major ions in seawater. using a density of 1.022 g/ml for seawater, convert the concentrations for the two ions in the question below into molality. ions g/kg mm na+ 10.781 480.57 k+ 0.399 10.46 mg2+ 1.284 54.14 ca2+ 0.4119 10.53 cl- 19.353 559.40 so42- 2.712 28.93 hco3- 0.126 2.11 total 35.067 n/a

Molarity of Ca²⁺ = 10.53 mM = 0.01053 M

Thus, moles of Ca²⁺ = Molarity × Volume

= 0.01053 M × 1 L

= 0.01053 moles

Density of solution = 1.022 g / ml

So, mass of solution = density × volume

= 1.022 g /ml × 1000 ml = 1022 g or 1.022 Kg

Mass of all ions in 1 Kg of seawater = 35.067 g

Mass of ions in 1.022 Kg = 1.022 Kg seawater × (35.067 g ions / 1 Kg seawater)

= 35.838 g

Therefore, mass of solvent, water = 1022 g - 35.838 g = 986.16 g or 0.98616 Kg

Molality of Ca²⁺ = moles / mass of solvent

= 0.01053 moles / 0.98616 Kg

= 0.0107 m

Similarly, molarity of HCO³⁻ = 2.11 mM or 0.00211 M

Consider a volume of 1 L (1000 ml) of solution

So, moles of HCO³⁻ = 0.00211 M × 1L = 0.00211 moles

So, mass of solvent, water = 1022 g - 35.838 g = 986.16 g or 0.98616 Kg

Molality of HCO³⁻ = moles of HCO³⁻ / mass of solvent

= 0.00211 moles / 0.98616 Kg

= 0.00214 m

since electrons are negative the answer is neagtaive

0.88m hope i am correct : )