Consider the reaction, 2 d(g) + 3 e(g) + f(g) => 2 g(g) + h(g) when h is increasing at 0.64 mol/ls, how quickly is e decreasing? give your answer to 3 decimal places.

The rate at which E is decreasing is 1.92  mol/ls.

The rate of reaction refers to how quickly or slowly that a reaction proceeds. The reactants disappear in a reaction while the products appear.

To obtain the rate at which E is decreasing when H is increasing at a rate of  0.64 mol/ls;

-ΔE/Δt = 3/1 ΔH/Δt = 3/1 (0.64 mol/ls) = 1.92  mol/ls

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the answer is c. nacl