Asolution of koh required 31.3 ml of 0.118 m hcl to reach neutralization. what mass of koh was in the titrated sample?

- 0.207 g of KOH.

Solution:- The acid-base reaction is known as neutralization reaction. In general, acid and base reacts to neutralize each other to form salt and water.

HCl is a strong acid and KOH is a strong base. At equivalence point the solution will be neutral. The balanced equation for the reaction of HCl with KOH is written as:

From the above reaction, they react in 1:1 mol ratio. From given molarity and volume, the moles of HCl are calculated and with the help of mol ratio the moles of KOH are calculated that could further be multiplied by its molar mass to get the grams.

Molar mass of KOH = 39.098 g + 16 g + 1.008 g = 56.106 g

The calculations are shown below using dimensional analysis:

= 0.207 g KOH

So, the mass of KOH in the titrated sample is 0.207 g.

it is a solid

explanation: