One of the reactions for rusting iron is as follows: 4fe + 3o2 → 2fe2o3 (mm fe: 55.85 g/mol; mm o2=32 g/mol; mm fe2o3=159.70 g/mol) if 63.98 g of oxygen gas is completely consumed, how many moles of iron (iii) oxide are formed? a. 1.333 mol b. 3071 mol c. 2.999 mol d. 6812 mol

A. 1.333 mol

Explanation:

To calculate the moles, we use the equation:

As oxygen is completely consumed, it is the limiting reagent and will limit the formation of .

According to stochiometry,

3 mole of produces 2 moles of

Thus 2 moles of will produce= moles of

Thus the correct answer is 1.333 moles

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

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